Question

Look at the rectangle and the square:
(on the screenshot)

Ada says that the length of diagonal SQ is two times the length of diagonal OM.

Is Ada correct? Justify your answer and show all your work. Your work should state the theorem you used to find the lengths of the diagonals.

Answer 1

Answer:

$(8 + 16) = 23 \\ (23 - 8) = 15 \\ therefore.ans \: is \: 15$

Answer 2

Answer:

No

Explanation:

Just say you are using the Pythagorean theorem. Anyways solving for SQ

A^2+B^2=C^2. 16^2+8^2=C^2. 256+64=C^2. 256+64=320. $\sqrt320$=17.8885438 or 18 when rounded. For OM, all squares have 8 inches on all sides. Just solve from there. A^2+B^2=C^2. 8^2+8^2=C^2. 64+64=C^2. 64+64=128. $\sqrt128$=

11.3137085 or 11 rounded. So 11 is not half of 18 so no, it's not 2x the length. Sorry if the equation looks confusing, I separated each one with a period.