look at the situation given in the figure 8.2 (a) and (b) if the bowling speed is 143 km h-1 in figure( a) what does it mean? what do you understand from the signbourd in figure (b)
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If a bowler is bowling from the speed of 143 km/hr and the boundary is 63 meters far, how much force should be applied from the batsman to hit a sixer?
Horizontal Distance, R = 63m
Velocity required, Vf = (9.8[g] x 63[R])^1/2 = 24.85 m/s (considering projection angle to be 45 degree)
Ball avg. mass, M = 0.16kg
Avg contact time, t = 0.002s
initial Horizontal Velocity of ball, Vb = 143 x 5/18 = 39.72m/s
change in horizontal velocity, Vx = Vb + Vf.cos45 = 57.3m/s
change in vertical velocity, Vy = Vf.sin45 = 17.57m/s
Total change in velocity, V = (Vx^2 + Vy^2)^1/2 = 59.93m/s
Total Force applied = M.V/t = 0.16 x 59.93/0.002 = 4794.4 N
Therefore, Force equivalent to 4.8 x 10^3 Newtons is to be applied
kindly correct me if I am wrong.
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