Question

Look at the two equations:
mc028-1.jpg3x + 6 = 21
mc028-2.jpg3x + 6 < 21
Which statement best describes the process used to solve the equations?
A.In both cases, subtract 6 from both sides, but reverse the inequality sign when doing that for the inequality.
B.In both cases, divide by –3 on both sides, but reverse the inequality sign when doing that for the inequality.
C.The process is exactly the same for solving the equation and solving the inequality.
D.The process for solving the equation is entirely different from solving the inequality.

Answer 1

$Given \: i )3x + 6 = 21$

/* Subtract 6 from bothsides of the equation, we get */

$\implies 3x + 6 - 6 = 21 - 6$

$\implies 3x = 15$

/* Dividing both sides of the equation by 3, we get */

$\implies \frac{3x}{3} = \frac{15}{3}$

$\implies x = 5$

$Given \: ii)3x + 6 \lt 21$

/* Subtract 6 from bothsides of the equation, we get */

$\implies 3x + 6 - 6 \lt 21 - 6$

$\implies 3x \lt 15$

/* Dividing both sides of the equation by 3, we get */

$\implies \frac{3x}{3} \lt \frac{15}{3}$

$\implies x \lt 5$

Therefore.,

$Option \: \pink { ( C ) } \: is \: correct.$

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Answer 2

Answer:

The answer is C.In both cases, divide by –3 on both sides, but reverse the inequality sign when doing that for the inequality.Step-by-step explanation:

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