Question

look the picture

please explain me

step by step explain​

Answer 1

$\huge \mathfrak \red{answer}$

$\bf{ \huge{ \underline{ \boxed{ \green{ \tt{616 {cm}^{2} \: }}}}}}$

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$\huge \mathfrak{correct \: question}$

A wire when bent in the form of the square encloses an areas of 484cm sqaure .the same wite now bent in the form of a circle. find the area enclosed by the circle..

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$\sf \underline{step \: by \: step \: explanation}$

$\rm{⟹let \: each \: of \: the \: sq uare\: be \: cm}$

$\rm{⟹then \: a = 484}$

$\rm{⟹a = \sqrt{484}cm = 22cm}$

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$\tt \red{⟹length \: of \: wire = permeter \: of \: square}$

$\tt{⟹4a = (4 \times 22) = 88cm}$

then now,

$\tt \red{⟹circumference \: of \: the \: circle \: formed = length \: of \: wire}$

$\tt{⟹2\pi \: r = 88}$

• where r = radius of the circle

$\tt{⟹r = (\frac{88}{2\pi})cm}$

$\tt{⟹ \frac{88 \times 7}{2 \times 22}}$

$\tt{⟹ = 14cm}$

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$\rm{area \: enclosed \: by \: the \: circle} =$

$\tt{⟹\pi {r}^{2} = \frac{22}{7} \times 14514 \: {cm}^{2}}$

$\tt{⟹616 {cm}^{2}}$

I hope it's help uh