Question

Looking into the sky one night, Tori wondered how far into outer space she would get if she drove a car for 3.21 × 103 hours at a rate of 70mph. She calculated and determined that a car travelling at 70 mph covers approximately 1.13 × 105 meters per hour.

Tori wrote this expression to determine the distance she would travel into outer space.

(3.21 × 103)(1.13 × 105)

Estimate the distance travelled

Answer 1

Here,

. time = 3.21 × 10³hours

. speed = 1.13 × 10⁵ meters per hour

$∴distance = speed \times time$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3.21 \times {10}^{3} \times 1.13 \times {10}^{5}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3.21 \times 1.13 \times {10}^{8}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3.627 \times {10}^{8} meters$