Question

loook at the attachement and sol;ve the questions

Answer 1

2.        P2 / P1 =  T2/ T1
           10^6  / 0.25 * 10^6  =  T2 / 300 K
         => T2 = 1200 K
       It will  blow up at  1200 K
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3. 
     P1 = 5 atm      T1 = 303 K          V1          n1      m1
               P1  V1 =  n1  R T1

     T2  = 293 K,       n1,   m1 same
     V2  = 160% V1 = 1.6 V1           =>    P2 =  P1 /1.6

     n3 =  n1 * 120%  = 1.2 n1            V3 = V2 = 1.6 V1
     T3 = ?        P3 =  P1

       P3 V3 / [P1 V1 ] =  n3 R T3 / [ n1 R T1 ]
       1.6 = 1.2 * T3 / 303

         T3 =  1.6 / 1.2 *    303 K

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4.

I think there is a misprint in the number :  10 deg C  increase in temperature or  10% increase in pressure....    Increase of 10 deg. C  cannot increase pressure by 10%.


m = 12 gm          T1 = 273+t deg K          V1 = v litre        P1 = 1 atm
M = 120        => n = 0.1  number of moles

if the increase of temperature is:  100 deg C
   T2 = 373+t  deg K            V2 = v litre        P2 = 1.10  atm

       P2/P1 = T2 / T1      =>     1.10 (273 + t) = 373 + t
               =>    t = 10 *  72.7  =  727 deg C

if the increase of pressure is 1 % only and increase of temperature is 10 degC,
             P2/P1 = 1.01 = 283+t  / (273+t)
                   t = 727 deg  C
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then calculate V as:
          v  = n *  R (273+t)  / P1          as all quantities are known