Math, asked by captainsharifa, 5 days ago

loop of wire is placed in a uniform magnetic field that is perpendicular to the plane of the loop , the strength of the magnetic field is 0.6.the area of the loop begins shrinking at constant rate of ∆A/∆t = 0.8m²s-¹​

Answers

Answered by unbeatablestar917
1

Answer:

Induced emf in the loop is given by

e=−B.

dt

dA

where A is the area of the loop.

e=−B.

dt

d

(πr

2

)=−Bπ2r

dt

dr

r=2 cm=2×10

−2

m

dr=2 mm=2×10

−3

m

dt=1s

e=−0.04×3.14×2×2×10

−2

×

1

2×10

−3

V

=0.32π×10

−5

V

=3.2π×10

−6

V

=3.2πμV.

Answered by sarfrazyousuf422
0

Answer:

b

Step-by-step explanation:

E=B.A

A=0.8/1s=0.8m2

E=(0.6)(0.8)

0.48V

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