loop of wire is placed in a uniform magnetic field that is perpendicular to the plane of the loop , the strength of the magnetic field is 0.6.the area of the loop begins shrinking at constant rate of ∆A/∆t = 0.8m²s-¹
Answers
Answered by
1
Answer:
Induced emf in the loop is given by
e=−B.
dt
dA
where A is the area of the loop.
e=−B.
dt
d
(πr
2
)=−Bπ2r
dt
dr
r=2 cm=2×10
−2
m
dr=2 mm=2×10
−3
m
dt=1s
e=−0.04×3.14×2×2×10
−2
×
1
2×10
−3
V
=0.32π×10
−5
V
=3.2π×10
−6
V
=3.2πμV.
Answered by
0
Answer:
b
Step-by-step explanation:
E=B.A
A=0.8/1s=0.8m2
E=(0.6)(0.8)
0.48V
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