Question

los tan 1" + log tan 2+ ... + log tan 85 -​

Answer 1

Answer:

its in attachment.....

Answer 2

ANSWER

=> 0

explanation :-

$log( \tan(5) ) + log( \tan(25) ) + log( \tan(65) ) + log( \tan(85) )$

[ Use logm +logn = logmn ]

$log( \tan(5). \tan(25) . \tan(65). \tan(85) )$

$log( \tan(90 - 85). \tan(90 - 65). \tan(65). \tan(85) )$

$log( \cot(85). \cot(65). \tan(65). \tan(85) )$

$log( \tan(85). \cot(85) ) .( \tan(65) . \cot(65) )$

$log(1 \times 1)$

$= > log(1)$

$= > 0$