Physics, asked by karthiheyan, 2 months ago

loss of kinetic energy in inelastic collision​

Answers

Answered by aditya120411kumar
2

Explanation:

An inelastic collision is a collision in which there is a loss of kinetic energy. While momentum of the system is conserved in an inelastic collision, kinetic energy is not. This is because some kinetic energy had been transferred to something else.

Answered by BrainlyBAKA
0

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From conservation of momentum

{m}_{1	}{v }_{1} \\

 = ({m}_{1} +{m }_{2} ){v}-{2}→{v}_{2} \\

= \frac{{m}_{1}}{{m}_{1} +{m}_{2}}×{ v }_{1}

The ratio of kinetic energies before & after collision is

\frac{{KE}_{f}}{{KE}_{i}} \\

= \frac{\frac{1}{2}×({m}_{1}+{m}_{2}) × (\frac{{m}_{1}}{{m}_{1} +{m}_{2}}×{ v }_{1})²}{\frac{1}{2}×{m}_{1}{v²}_{1}} \\

 = \frac{{m}_{1}}{{m}_{1} +{m}_{2}}{×}{ v }_{1}

The fraction of kinetic energy lost is

\frac{{KE}_{i} – {KE}_{f}}{{KE}_{i}} \\

 = \frac{1 –( \frac{{m}_{1}}{{m}_{1} +{m}_{2}})×{ v }_{1}}{{KE}_{i}} × {KE}_{i} \\

 = \frac{{m}_{2}}{{m}_{1} +{m}_{2}}×{ v }_{1}

Hence energy always loss in inelastic collision.

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