Question

lost of problem i have

Answer 1

$given \: \: y = \frac{1}{x} \\ after \: \: increasing \: \: x \: \: by \: \: 20\% \\ {y}^{'} = \frac{1}{1.2x} \\ \%decrease \: \: in \: \: y \: \: is \\ \frac{y -{y}^{'} }{y} \times 100 = \frac{\frac{1}{x} -\frac{1}{1.2x} }{\frac{1}{x}} \times 100 \\ (1 - \frac{1}{1.2} ) \times 100 = \frac{100}{6} \\ = \frac{50}{3} = 16 \frac{2}{3} \% \\ option \: \: (b)$