Math, asked by yashkkhandelwal23012, 5 months ago

Lovleen says, If Gita gives me ₹40, she will have half as much as Ashish. But, if Ashish gives me ₹40 then three of us will have the same amount. What is the total amount of money that Lovleen, Gita, and Ashish have among themselves?

Please give the explanation too.

Answers

Answered by tamana8950
1

Answer:

Let A has Rs a

B has Rs b

C has Rs c

Now, According to question,

b−40=

2

c

2b−80=c (I)

Also, a+40=b=c−40 (II)

thus, from I and II,

2b−80=b+40

b=120

Hence, a=b−40=120−40=80

and, c=2b−80=2×120−80=160

Total amount = a+b+c=80+120+160=360

Step-by-step explanation:

just need to understand the math word problems nothing else

Answered by khashrul
1

Answer:

The total amount of money that Lovleen, Gita and Ashish have among themselves is ₹360.

Step-by-step explanation:

Let's assume that Lovleen has ₹x, Gita has ₹y and Ashish has ₹z.

According to the problem:

If Gita gives ₹40 to Lovleen, Geeta will have ₹(y - 40) = ₹\frac{z}{2} . . . . . . . . . .  (i)

And, If Ashish gives ₹40 to Lovleen, Lovleen will have ₹(x + 40),

Ashish will have ₹(z - 40) and Gita will still have ₹y:

x + 40 = y = z - 40 = 2y - 80 - 40  [using equation (i)]

∴ y = 2y - 120

∴ y = 120

x = y - 40 = 80

z = 2y - 80 = 240 - 80 = 160

∴ x + y + z = 80 + 120 + 160 = 360

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