Question

low price of 3 chairs and tables 4500 rupees price of 5 chairs and 3 table is 7000 Rupees then find the total price of two chairs and tables​

Answer 1

Step-by-step explanation:

take cost of chair = X

and cost of table =Y

3x+3y=4500

5x+3y=7000

by additive inverse it becomes

3x+3y=4500

-5x-3y=-7000

it becomes

-2x=-2500

minus sinse get cancelled

x=1250

from substituting from 1st equation

y=3(1250)+3y=4500

y=3750+3y=4500

3y=4500-3750

3y=750

y=750/3

y=250

plz mark me in brainiest answer

Answer 2

Answer:

The total price of two chairs and two tables is rupees 4000.

Step-by-step explanation:

3x + 2y = 4500 ... (1)

From the second condition,

5x + 3y = 7000 ... (2)

Multiplying equation (1) by 3 and equation (2) by 2,

9x + 6y = 13500 ... (3)

10x + 6y = 14000 ... (4)

Subtracting equation (3) from equation (4),

(10x + 6y = 14000)

-(9x + 6y = 13500)

——————————

x + 0 = 500

=> 2x = 2 × 500 = 1000 ... (5)

Substituting x = 599 in equation (1)

3(500) + 2y = 4500

=> 1500 + 2y = 4500

=> 2y = 4500 - 1500

=> 2y = 3000 ... (6)

Now, the price of 2 chairs and 2 tables is

Rupees(1000 + 3000) [From (5) and (6)]

= rupees 4000

Hence, the total price of 2 chairs and 2 tables is rupees 4000.

Hope it helps :)