Question

Lowering of vapour pressure due to a solute in 1 molal aqueous solution at hundred degree celsius is

Answer 1

Answer:

Lowering of vapour pressure due to a solute in 1 molal aqueous solution at hundred degree celsius is 13.44 torr

Explanation:

1 molal means 1 mole of solute in 1kg of water.

By using the formula :

Relative lowering of Vapour pressure :

p°-p/p° =Xi =mole fraction

p°-p=Δp= Xi . p°

=(1/1+1000/18)x760

=(1/ 1+55.55) x 760

(1/56.55) x 760

=0.0176x760

=13.44 torr