Question

LPG is a mixture of n-butane & iso-butane What is the volume (in Lt) of oxyen needed to burn 1 kg of LPG at 1 atm, 273 K?​

Answer 1

Answer:

In Lt 670K is need with N butane

Answer 2

Explanation:

C4H10 + 13/2 O2 => 4CO2 + 5H2O

58gm 13/2 × 32

58gmCH4 required volume Of O2 at NTP = 13/2 × 24lit

So, 1kg of CH4 requires = 13×1000/2×58 ×24lit = 2690L