Question

ls it impossible... no one is answering correctly.. pls help with this question.. pls​

Answer 1

Answer:

63=16

bro wrong question waste of time

Step-by-step explanation:

given data:-

$\frac{1}{x + 7} + \frac{1}{x + 9} = \frac{1}{x + 6} + \frac{1}{x + 10}$

asked:-

•value of x

∆. solution:--

$\frac{(x + 9) + (x + 7)}{(x + 7) \times (x + 9)} = \frac{(x + 10) + (x + 6)}{(x + 6) \times (x + 10)} \\ \\ \frac{2x + 16}{ {x}^{2} + 9x + 7x + 63} = \frac{2x + 16}{ {x}^{2} +10x + 6x + 60 } \\ \frac{1}{ {x}^{2} + 16x + 63 } = \frac{1}{ {x}^{2} + 16x + 60 } \\ {x }^{2} + 16x + 63 = {x}^{2} + 16x + 60 \\ 63 = 16$