lsinA+mcosA+n=0
l'sinA+m'cosA+n'=0
prove that (m.n'-m'n)2 + (nl'-ln')2=(lm'-l'm)2
Answers
We have-
lsinA +mcosA+ n=0
and l'sinA m'cosA+n'=0
Now taking sinA and cosA as variables we can apply the principal of cross multiplication.
sinA cosA 1
m n L m
m n' L' m'
using cross multiplication
sinA/(mn'-m'n) = cosA/(nl'-n'l) = 1/(lm'-l'm)
⇒sinA=mn'-m'n/lm'-l'm
squaring both the sides,we get
sin²A=(mn'-m'n/lm'-l'm)² ..........(1)
and cos²A=(mn'-m'n/lm'-l'm)² ........(2)
adding boththe equations, we get
1=(mn'-m'n)²+(nl'-n'l)²/(lm'-l'm)² ........ {sin²A+cos²A=1}
⇒(lm'-l'm)²=(mn'-m'n)²+(nl'-n'l)²
Hence proved.