<13. A stone drops from edge of a roof it passe a window 2m high in 0.1 secod .
hw far is roof above the top of widow
Answers
Answer:
The object is falling under gravity. As it is moving towards the earth, Its acceleration is +g.
As it is dropped, It has initial velocity = 0 .
The stone passes the window of 2m high in 0.1s .
Let the distance between the roof and that window be " k " k
m and the time taken to reach that " k "m is t
That is k = 1/2gt² ( From the second equation of motion)
Given that, Stone passes through the window in 0.1 second.
So it travels k+2 m in t + 0.1seconds .
k + 2 = 1/2g(t+ 0.1)²
Substituting the value of k,
1/2gt² + 2 = 1/2g(t²+0.01 + 0.2t)
1/2gt² - 1/2gt² + 2 = 0.005 g + 0.1gt
2 = 0.005 * 10 + 0.1(10)t
2= 0.05 + t
2 - 0.05 = t
1.95 = t.
Therefore, The stone takes 1.95seconds to travel from roof to top of the window.
Now, We have to find The distance between roof and top of the window ( k)
k = 1/2(10)(t²)
k = 5t²
k = 5(1.95)²
k = 19.0125
Explanation:
Correct Question -
A stone is dropped from edge of a roof .It passes a window 2m high in 0.1 second. How far is roof above the top of window.
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Answer
(refer to the attachment)
Given -
s = 2m
t = 0.1 sec
a = g = 9.8
where
s is distance travelled.
t is time taken.
a is acceleration due to gravity.
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To find -
Distance between roof and window h
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Formula used -
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Solution -
Substituting the value in
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u = 0 m/s ( stone is dropped )
v = 19.51 m/s
g = 9.8 m/s²
Substituting the value in
Thus the roof is 19.42 m from the upper end of window.
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