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18. Find n if:
2n-6
-0-0-6" (39%{@T-CE)
23)
6
3n - 13
3
20
4
12.
3
5.
9
3
3
X Х
C.
d.
X Х
25
25
5
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Answer:
a. n=9
b. n=5
c. n=2
d. n=5
Step-by-step explanation:
a. [(4/49)^5]*[(4/49)^n-3]=(2/7)^16
[(2/7)^5*2]*[(2/7)^n-3]=(2/7)^16
[(2/7)^10]*[(2/7)^n-3]=(2/7)^16
10+(n-3)=16
n-3=16-10
n=6+3=9
The next three sums ate given in the picture
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