Question

<A CB NOB proved
of the
Brove that angle subtended at the centre
arde in the double of the angle subtended at the
circumference
To prove - AOB = 2ACB
Spam=reported​

Answer 1

To prove : ∠POQ=2∠PAQ

To prove this theorem we consider the arc AB in three different situations, minor arc AB, major arc AB and semi-circle AB.

Construction :

Join the line AO extended to B.

Proof :

∠BOQ=∠OAQ+∠AQO

Also, in △ OAQ,

OA=OQ

Therefore,

∠OAQ=∠OQA

∠BOQ=2∠OAQ

Similarly, BOP=2∠OAP

Adding 2 & 3, we get,

∠BOP+∠BOQ=2(∠OAP+∠OAQ)

∠POQ=2∠PAQ

follow m

Answer 2

Answer:

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