<ABC is inscribed in arc ABC of circle. If m(arc ABC)=210°, then find <ACB
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Step-by-step explanation:
Since, Here the angle abc is inscribed in arc of circle with Center O,
Also, m\angle ACB = 65^{\circ}m∠ACB=65
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⇒ By the Central angle theorem,
m\angle ABC = 2 \times m\angle ACB = 2 \times 65^{\circ} = 130^{\circ}m∠ABC=2×m∠ACB=2×65
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=130
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Thus, the length of major arc ACB = 360^{\circ} - 130^{\circ} = 230^{\circ}360
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−130
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=230
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