Question

<ACD is an exterior angel of triangelABC. If <ACD = 122 degree and <A=68 degree then <B=___
a)64
b)54
c)44
d)68​

Answer 1

Answer:

it is not triangle

please like

Answer 2

Step-by-step explanation:

• We know that the value of exterior angel is equal to sum of two opposite angle .

•Here in ∆ABC <ACD is a exterior angel

So

<ACD = <A + <B

122 = 68 + < B

< B = 122 - 68

< B = 54 °