Math, asked by Anonymous, 10 months ago

<br /> $<p style="color:cyan;font-family:cursive;background:black;font size:25px;">Q. In an isosceles triangle, the base angles are equal. The vertex angle is 40°. What are the base angles of the triangle? (Remember , the sum of three angles of a triangle is 180°) ANSWER SHOULD COME -LOWEST MARKS =40$ . <br /><br /><br /><br /><br /> $<body aquacolor=b>$ <br /> $\large\orange{}$ <br /> $<font color=red>$ <br /> $<marquee>Chapter- Simple Equation</marquee>$ <br /><br /><br /><br /> PLEASE ANSWER FAST<br />

Answers

Answered by EuphoricEpitome

6

Step-by-step explanation:

sum of all angles of triangle = 180°.

take base angle as x.

vertex angle = 40

40+x+x = 180

2x = 180-40

2x = 140

x = 140/2

x= 70°.

sum of base angles = 140°.

base angles = 70° each.

Answered by wastebasket

0

HEY MATE,

If vertex angle = 40°

let the two equal angles be x°

Now, In the Triangle,

x + x + 40° = 180° ( ASP of ∆ )

2x = 140

x = 140/2 = 70°

Hence, x = 70°

Thus, The base angles of triangle are 70° *each***. ✔️

THANK YOU...✌️

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