Math, asked by Anonymous, 11 months ago

<br />&lt;p style="color:cyan;font-family:cursive;background:black;font size:25px;"&gt;Q.  In an isosceles triangle, the base angles are equal. The vertex angle is 40°. What are the base angles of the triangle? (Remember , the sum of three angles of a triangle is 180°) ANSWER SHOULD COME -LOWEST MARKS =40 . <br /><br /><br /><br /><br />&lt;body aquacolor=b&gt; <br />\large\orange{} <br />&lt;font color=red&gt; <br />&lt;marquee&gt;Chapter- Simple Equation&lt;/marquee&gt; <br /><br /><br /><br /> PLEASE ANSWER FAST<br />​

Answers

Answered by Anonymous
35

&lt;body bgcolor=black&gt;&lt;marquee direction="up"&gt;&lt;font color=pink&gt;

he sum of all angels of a triangles =180

Let the base angles be 'x'

Therefore,

x+x+40=180

2x=180-40

2x=140

X= 140/2

x = 70

Hence the base angles of the triangle are 70, 70

&lt;body bgcolor=red&gt;&lt;marquee direction="down"&gt;&lt;font color=yellow&gt; Hope this helps you

Answered by Anonymous
0

Yours answer is x=70.....

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