Math, asked by Anonymous, 9 months ago

$Q. In an isosceles triangle, the base angles are equal. The vertex angle is 40°. What are the base angles of the triangle? (Remember , the sum of three angles of a triangle is 180°) ANSWER SHOULD COME -LOWEST MARKS =40$ . $<body aquacolor=b>$ $\large\orange{}$ $$ $<marquee>Chapter- Simple Equation</marquee>$ PLEASE ANSWER FAST 

ANSWER SHOULD COME=-LOWEST MARKS=40°

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Answered by Anonymous

$ he sum of all angels of a triangles =180Let the base angles be 'x'Therefore,x+x+40=1802x=180-402x=140X= 140/2x = 70Hence the base angles of the triangle are 70, 70$ . $<body aquacolor=b>$ $\large\orange{}$ $$ $<marquee>Hope this helps you</marquee>$

Answered by avani1396

Let the base angles be ′ x ′

Therefore,

x+x+40 ∘ =180 ∘

[Given]

2x=180 ∘ −40 ∘

2x=140 ∘

x=70 ∘

Hence,

The base angles of the triangle are 70 ∘ ,70 ∘.

Hope so it is helpful.. Mark me as brainliest.. Thankyou

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