Question

<br />The ages of Leena and Heena are in the ratio 7:5 . Ten years hence, the ratio of their ages will be 9 : 7. Find their present ages.

Answer 1

Let the ages of Leena and Heena be 7x, 5x
After 10 years,
Their ages = 7x+10, 5x+10
A/Q 7x+10/5x+10 = 9/7
7(7x+10) = 9(5x+10)
49x+70 = 45x+90
4x = 20
x = 5
Present age of Leena = 7x = 35
Present age of Heena = 5x = 25

Answer 2

Answer:

The Present ages are -

Leena = 35 years

Heena = 25 years

Step-by-step explanation:

Given :

Ages of Leena and Heena are in Ratio = 7 : 5

Ratio after 10 Years = 9 : 7

To Find :

Their present Ages

Solution :

Let the present Ages be -

• Leena as 7x
• Heena as 5x

$\rule{300}{1.5}$

➡ (7x + 10)/(5x + 10) = 9/7

➡ 7(7x + 10) = 9(5x + 10)

➡ 49x + 70 = 45x + 90

➡ 49x - 45x = 90 - 70

➡ 4x = 20

➡ x = 20/4

➡ x = 5

$\rule{300}{1.5}$

Heena's age =

➡ 5 × 5

➡ 25

$\rule{300}{1.5}$

Leena's age =

➡ 7 × 5

➡ 35

$\therefore$ The Present ages are -

• Leena = 35 years
• Heena = 25 years