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It has given that, sides of a right angled triangle are ; 6 cm, 8cm and 10 cm.
we have to find the length of perpendicular drawn to the hypotenuse from the opposite vertex.
solution : let length of perpendicular drawn to the hypotenuse is x cm.
let right angled triangle is ∆ABC where B is right angle. and we draw a perpendicular B to AC which touches AC at T.
here, ∠BAT = ∠BAC
and ∠BTA = ∠ABC
so, ∆ATB ~ ∆ABC
then, AB/AC = BT/BC
⇒6cm/10cm = BT/8 cm
⇒BT = 48/10 = 4.8 cm
Therefore the length of perpendicular drawn to hypotenuse is 4.8 cm
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