Lt.
In the figure given at right, find :
(i) Z ACD
(ii) Z AED
15°E
529
B
40°
С
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Answer:
According to Exterior Angle Property in △ABC
∠ACD=∠CAB+∠CBA=35
o
+50
o
=85
o
Applying same property
∠AED=∠ACD+∠ECD=85
o
+30
o
=115
o
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