Question

lt. [log(sin7x + cos7x)]÷[sin3x]
x-->0


======= ???????​

Answer 1

$|| | \frac{ \sin(x) }{x} = 1 || \\ = > log( \sin(7x) + \cos(7x) ) \div \sin(3x) \\ = > \frac{ ln(7x + 1) }{3x} \\ = > || log(x + 1) \div x = 1 || \\ = > 7 \frac{ log(7x + 1) }{3 \times 7x} \\ = > \frac{7}{3}$