Question

Lt-pi/2 (1-sinx)/cosx

Answer 1

Answer:

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Step-by-step explanation:

We have to find the value of lim x-->pi/2 [(1 - sin x)/cos x]

Substituting x = pi/2, gives us 0/0, which is indeterminate. This allows us to use the L'Hopital's rule and substitute the numerator and denominator with their derivatives

=> lim x-->pi/2 [(-cos x)/-sin x]

substituting x = pi/2

=> 0

The required value of the limit is 0.