Question

lt root x-2, x tends to 2
1)0
2)1
3)-1
4)does not exist ​

Answer 1

lim X tends to 2

$\sqrt{x - 2}$

sᴏʟᴜᴛɪᴏɴ

rationalise the term

then ,

lim X tends to 2

$\sqrt{x - 2} \times \frac{ \sqrt{x + 2} }{ \sqrt{x + 2} }$

we know that √ a × √ b = √ab

then

lim x tends to 2

$\frac{ \sqrt{x {}^{2} - 4 } }{ \sqrt{x + 2} }$

then the answer is 0

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