Math, asked by praneethreddy5, 1 year ago

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x 2. limit X tends to 2 X root 2 minus 2 root 2 by x minus 2 ​

Answers

Answered by mysticd
7

 The \: value \: of\: \lim_{x \to2}\: \frac{x\sqrt{2}-2\sqrt{2}}{x-2}

 = \lim_{x \to2} \frac{\sqrt{2}(x-2)}{(x-2)}

/* After cancellation of (x-2), we get */

 = \lim_{x \to2} \sqrt{2} \\= \sqrt{2}

Therefore.,

 \red{The \: value \: of\: \lim_{x \to2} \frac{x\sqrt{2}-2\sqrt{2}}{x-2}}\green {= \sqrt{2}}

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