Question

lt x tends to 0 (√1+x+x^2)-1/x is​

Answer 1

→01+x−−−−−√−1−x−−−−−√x=limx→01+x−−−−−√−1−x−−−−−√x⋅1+x−−−−−√+1−x−−−−−√1+x−−−−−√+1+x−−−−−√=limx→0(1+x)−(1−x)x(1+x−−−−−√+1−x−−−−−√)=limx→021+x−−−−−√+1−x−−−−