lt x tends to0 e^x-1/root1+x-1
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Step-by-step explanation:
√
x
+
1
−
1
x
=
(
√
x
+
1
−
1
)
(
√
x
+
1
+
1
)
x
(
√
x
+
1
+
1
)
=
x
+
1
−
1
x
(
√
x
+
1
+
1
)
=
1
√
x
+
1
+
1
so
lim
x
→
0
√
x
+
1
−
1
x
≡
lim
x
→
0
1
√
x
+
1
+
1
=
1
2
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