<XYZ is bisected by YP. l is any point on YP and MLN is perpendicular to YP. Prove that LM=LN.
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LY=LY (common side)
<LYM=<LYN. (P is the angle bisector)
YM=YN. (Side opposite to equal angle are equal)
hence by SAS <LYM CONGRUENT TO <LYN
THEREFORE LM=LN (CPCT)
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LY =LN ( common side)
<LYM =<LYN ( P is the angle bisector)
YM = YN ( Side opposite to equal angle are equal)
hence by SAS angle LYM congruent to TYN
therefore LM=LN ( CPCT)
here is your answer hope it helpfull
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