Lucille spent 12% of her weekly earnings on
DVDs and deposited the rest into her savings account. If she spent $42 on DVDs, how much did she deposit into her savings account? Also what is 12% of $42?
Answers
Answer:
Step-by-step explanation:
Number of % spend for the DVD = 12%
Number of $ spend for the DVD = $42
Number of $ per a % = 42 ÷ 12
= 3.5 $ per %
Total weekly earning is 3.5 × 100
= $3500
Number of $ she deposited for her savings
= 3500 - 42
= 3458
$3458 is deposited in her savings account.
➤ Given :-
Percent of weekly earnings spent :- 12%
Rupees of weekly earnings spent :- $42
➤ To Find :-
Amount deposited to her account and 12% of $42.
★ How to do :-
Here, we are given with the percent of the amount spent and the amount spent on DVD. We are said that she deposits the remaining amount to her savings account. We are asked to find the money that she deposits into her account and we are should also find the 12% of the spent rupees. So, first we should find her total weekly earnings by using the money spent and the percent of money spent. Then, we should find the saved money by subtracting the total salary and the spent salary. Later, we can find the 12% of the spent amount. The spent amount is the money which is spent for buying the DVDs. So, let's solve!!
➤ Solution :-
Total earnings of Lucille :-
Let the total salary be y.
Write the percentage as fraction and 'of' as multiplication sign.
Shift the number 42 from RHS to LHS.
Write the fraction in lowest form by cancellation method.
Now, multiply the remaining numbers.
Write the obtained fraction in lowest form to get the the total amount.
Now, let's find the money that she deposited in her savings account.
Money deposited in savings account :-
Substitute the given values.
Subtract the values to get teh answer.
Now, let's find the 12% of money spent on DVD.
12% of $42 :-
Write the percentage as fraction and 'of' as multiplication sign.
Write the denominator and the whole number in lowest form by cancellation method.
Multiply the remaining numbers.
Simplify the fraction to get the answer.