Lucy is taking the train to see her lover on Valentine's day! The train is 100 meters long and it takes 30 seconds to cross a 400m bridge. What speed is the train going at?
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Given:The length of train=100m
Length of bridge=400m
Total distance travelled by the train through the bridge=(length of bridge)+(length of train)=400+100=500
[This is because after the front of the train passes through the bridge... the backside of the train is still traversing through the bridge and that extra 100m also needs to be included while claculating the total traversed distance and time)
speed of train=(Total distance traversed)÷(total time taken)=500/30=16.667m/s.
Hope it helps...
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Leukonov/Olegion
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length of train = 100m
length of bridge = 400m
distance travelled = (100 + 400)m = 500m
time taken = 30 sec.
speed of train = 500m /30 sec. = 16.66667 m/sec.
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