Question

Lucy rolls 2 fair dice and adds the results from each. Work out the probability of getting a total less than 10.

Answer 1

Solution :-

we know that, when two dice are tossed once, then possible events will be

• (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
• (2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
• (3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
• (4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
• (5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
• (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
• Total = 36 .

so,

→ Total favourable outcomes = sum less than 10 :-

• (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
• (2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
• (3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
• (4,1), (4,2), (4,3), (4,4), (4,5)
• (5,1), (5,2), (5,3), (5,4)
• (6,1), (6,2), (6,3)
• Total = 30

therefore,

→ Required Probability = Number of favourable outcomes / Total number of outcomes = 30 / 36 = (5/6) (Ans.)

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