Question

Luke and Aisha are traveling on the same road, in the same direction. Luke is driving at a rate of 50 mi/h, and Aisha is driving at a rate of 55 mi/h. Write and solve an inequality to find when Aisha will be ahead of Luke on the highway. Let x represent time in hours. 15 mi Aisha Luk

Answer 1

x is the time, in hours, then:

x(55)=x(50)+15

5x=15

x=3 hours before Aisha is ahead of Luke

☺☺☺☺ please mark

Answer 2

let us assume  (x) be the time given in hours

as Luke is driving at a rate of 50 minute/h.

and Aisha is driving at 55miniute/h.

x(55)=x(50)+15

5x=15

x=3 hours before Aisha is ahead of Luke