Question

Luke is making a cylinder using 2 circles cut from paper as well as a rectangular sheet of paper. Each circle has a diameter of 7 cm, and the rectangular sheet of paper has a length of 10 cm. Luke knows that the width of the paper must be the same as the perimeter of the circle. What is the 22 width of the paper? Use
$\pi = \frac{22}{7}$
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Answer 1

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Luke is making a cylinder using 2 circles cut from paper as well as a rectangular sheet of paper. Each circle has a diameter of 7 cm, and the rectangular sheet of paper has a length of 10 cm. Luke knows that the width of the paper must be the same as the perimeter of the circle. What is the 22 width of the paper? Use

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We know that the curved surface area of a right circular cylinder with radius r and height h is CSA=2πrh.

It is given that the length of the rectangular sheet is

$1 = 44cm[tex] </p><p></p><p>and the height of the sheet is h=20 cm.</p><p></p><p></p><p> <strong><u>S</u></strong><strong><u>i</u></strong><strong><u>n</u></strong><strong><u>c</u></strong><strong><u>e</u></strong><strong><u>,</u></strong><strong><u> </u></strong>he <strong>cylinder</strong> is formed among the length, therefore, length of rectangular sheet is equal to <strong><u>circumference</u></strong> of base that is:</p><p></p><p>[tex]\pi = \frac{22}{7}$

$Divide \ and \ find \ the \ π$

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Answer 2

Answer:

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