Question

LUN15 -
UT
1. 5.0 g sample of calcium carbonate (CaCO3), contaminated with a volatile impurity, left a residue
of 2.2 g on strong heating. What is the percentage of pure CaCO3 in the sample ? [Ca = 40; C = 12;
0 = 16]. 9
[78.6%)​

Answer 1

Answer:

In 100 g CaCO

3

, 40 g Ca is present.

In 4 g CaCO

3

, Let x g Ca be present

4

x

=

100

40

⟹x=1.6 g