lx + my = a.
mx + ly = b.
solve this equation
Answers
Answered by
4
lx + my = a ----------(1)
mx + ly = b-----------(2)
multiply l with equation (1) and m with equation (2)
l²x + mly = al
m²x + mly = bm
=================
subtracting ,
l²x - m²x = al - bm
( l² - m²)x = ( al -bm)
x = ( al - bm)/( l² - m²)
similarly ,
multiply m with equation (1) and l with equation (2)
mlx + m²y = am
mlx + l²y = bl
==============
subtracting
( m² - l²)y= ( am - bl)
y = ( am - bl)/( m² - l²)
mx + ly = b-----------(2)
multiply l with equation (1) and m with equation (2)
l²x + mly = al
m²x + mly = bm
=================
subtracting ,
l²x - m²x = al - bm
( l² - m²)x = ( al -bm)
x = ( al - bm)/( l² - m²)
similarly ,
multiply m with equation (1) and l with equation (2)
mlx + m²y = am
mlx + l²y = bl
==============
subtracting
( m² - l²)y= ( am - bl)
y = ( am - bl)/( m² - l²)
Anonymous:
thank-you
my + pleasure
xD
i wrote down with both the methods
means you want this answe with both method
No, sinhaabhishek has used the other method no
Answered by
4
see attachment.
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hope it will help u...
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hope it will help u...
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thanks for your answer
wlcm (^_^)
thank you so much
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