Question

lycos freedom on an infinitely long straight uniformly charged wire and hence obtain an expression for electric field​

Answer 1

Answer:

By using Gauss theorem we contruct a Gaussian suface (cylinder) aroung the long wire. As we know, Lambda is ration of small charge by small distance i.e., dq/dl Therefore, lambda×dl=dq Integrated both sides we get, Lambda L = Qenclosed According to our knowledge electric flux is dot product of E.ds which further equals to Qenclosed / epsilon, Cos angle is 0° Therefore, after integration we get E= lambda/2πrepsilon.