Question

M 1 = 40 kg
U 1= 5m/s
M₂ = 60 kg
U 2 = 4 m/ s
v 1 = ?
v 2= ?​

Answer 1

Answer:

v1= c2v2/c1

v2=u2+2as

Explanation:

THIS ANSWER IS REALLY CORRECT

Answer 2

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According to law of conservation of momentum, the total momentum in a system of bodies remain same if no external force acts on the system.

Or we can say sum of initial momentum of both bodies = sum of final momentum of both bodies.

Mathematically we represent it by

$m_1 × u_1 + m_2 ×u_2 = m_1 × v_1 + m_2 × v_2$

Now in most cases the the both bodies collide or their final velocity becomes same.

Thus we can say.

$v_1 = v_2$

Let's say --->

$v_1 = v_2 = v$

Now it is given that ---->

$m_1 = 40kg$

$u_1 = 5m \div s$

$m_2 = 60kg$

$u_2 = 4m \div s$

$v_1 = v_2 = v =?$

Now after inputting the given values in law of conservation of momentum we get that :

$40(5) + 60(4) = 40v + 60v$

$200 + 240 = 100v$

$440 = 100v$

$v = \frac{440}{100}$

$v = 4.4$

Thus the final velocity with which both bodies move is 4.4m/s.

Now we can say that:

$v_1 = 4.4$

$v_2 = 4.4$

Both velocities are same.

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BY SCIVIBHANSHU

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