Question

m-1-(m-1)*2 + am-a factorise

Answer 1

Q:(m - 1 ) - (m - 1)^2 + am - a

=(m - 1 ) - ( m - 1 )^2 + a( m - 1 )

=(m - 1 ) { 1 - (m - 1 ) + a }

=(m - 1 ) ( 1 - m + 1 + a )

=(m - 1 ) (2 + a - m )

=(m - 1 ) (a - m + 2 )
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【 hope helps 】 ________________________

Answer 2

Q) m-1-1(m-1)^2+am-a
=m-1-1[(m^2)-2m+1^2]+am-a
=m-1-1(m^2-2m+1)+am-a
=m-1-m^2+2m-1+am-a
=m-m^2+2m-2+am-a
=m(1-m)-2(1-m) -a(1-m)
=(m-2-a) (1-m)