m+1/m = √3 , find the value of m³ + 1/m³
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Answered by
3
Answer:
M+1/m=root3 - - - - - - - - (eq. - 1)
On cubing both side, we get,
(M)^3+(1/m)^3+3(m)(1/m)[m+1/m] = (root 3) ^3
(M)^3+(1/m)^3 = 3 root 3 - 3[m+1/m]
(m) ^3+(1/m)^3= 3root3 - 3root3
(m)^3 + (1/m) ^3 = 0
HENCE, THE VALUE IS 0
Answered by
3
Since,m+1/m=root3
Value of m^3+1/m^3=
(m+1/m)^3-3(m+1/m)(m)(1/m)
(Root3)^3-3(root3)(1)
(3)(root3)-3(root3)
0
Hope it will help you!!
Value of m^3+1/m^3=
(m+1/m)^3-3(m+1/m)(m)(1/m)
(Root3)^3-3(root3)(1)
(3)(root3)-3(root3)
0
Hope it will help you!!
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