(m-1/m=5)finf value of mcube -1/mcube
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Answer:
we will find m³- 1/m³. by using identity
(a-b)³ = a³ - b³ -3ab(a-b)
so,
(m-1/m)³ = m³ - 1/m³ -3×m×1/m (m-1/m)
(5)³ = m³ - 1/m³ -3×5
125 = m³ - 1/m³ -15
m³ - 1/m³ = 125 + 15
m³ - 1/m³ = 140
Step-by-step explanation:
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