Question

m =1 , n=2 ,p=0 find the value​

Answer 1

Answer:

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Step-by-step explanation:

$\frac{1}{2} {m}^{4} + \frac{2}{3} {m}^{2} {p}^{2} - \frac{1}{8} {m}^{2} {n}^{2} + {n}^{3} \\ substituting \: the \: values \\ \frac{1}{2} ({1}^{4}) \: + \: \frac{2}{3} ({1}^{2})({0}^{2}) \: - \frac{1}{8} ({1}^{2}) ({2}^{2}) \: + \: ({2}^{3}) \\ \frac{1}{2} + \: 0 \: - \frac{4}{8} + \frac{8}{1} \\ = \frac{4 - 4 + 64}{8} \\ = \frac{64}{8} \\ = 8$