Question

(m+1)x^2+2(m+1)x+(m-2)=0 has equal roots then find 'm'.
​

Answer 1

Step-by-step explanation:

For the quadratic equation,

(m+1)x² + 2(m+1)x + (m-2) = 0

Discriminant = b² - 4ac = [2(m+1)]² - 4.(m+1).(m-2)

Since roots are equal roots

4(m+1)² - 4(m² - m - 2) = 0

4[m²+2m+1-m²+m+2] = 0

4[3m+3] = 0

m = -1