M 12
7sin 45° +cosec 60° -2 tan 30°
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7(1)'2+(2/√3)'2-2(1/√3)'2
7+4/3-2/3
23/3 is the right answer
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Answer:
7sin^2 45°=7×(1/root2)^2
= 7(1/2)
= 7/2
cosec^2 60°=(2/root3)^2
=4/3
2tan^2 30°=2×(1/root3)^2
=2(1/3)
=2/3
SO, 7/2+4/3-2/3
=7/2+2/3
= 25/6 is the answer
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