Question

(m^2+14m+31)÷(m+10)​

Answer 1

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By the remainder theorm.

m+10=0

m=(-10)

Then A/Q

$\sf m{}^{2}+14m+31 \\ \sf\implies (-10){}^{2}+14×(-10)+31\\ \sf\implies 100-140+31 \\ \sf\implies -40+31\\ \sf\implies (-9)$